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@mod @mod_forum Feature: Forum discussions can be split In order to manage forum discussions in my course As a Teacher I need to be able to split threads to keep them on topic. Background: Given the following "users" exist: | username | firstname | lastname | email | | teacher1 | Teacher | 1 | teacher1@example.com | | student1 | Student | 1 | student1@example.com | | student2 | Student | 2 | student2@example.com | And the following "courses" exist: | fullname | shortname | category | | Science 101 | C1 | 0 | And the following "course enrolments" exist: | user | course | role | | teacher1 | C1 | editingteacher | | student1 | C1 | student | | student2 | C1 | student | And the following "activities" exist: | activity | name | course | idnumber | type | | forum | Study discussions | C1 | forump1 | general | And the following "mod_forum > discussions" exist: | forum | course | user | name | message | | forump1 | C1 | teacher1 | Photosynthesis discussion | Lets discuss our learning about Photosynthesis this week in this thread. | And the following "mod_forum > posts" exist: | user | parentsubject | subject | message | | student1 | Photosynthesis discussion | Mass number | Can anyone tell me which number is the mass number in the periodic table? | | student2 | Mass number | | I would also like to know this | Scenario: Split a forum discussion Given I am on the "Study discussions" "forum activity" page logged in as teacher1 And I follow "Photosynthesis discussion" When I follow "Split" And I set the following fields to these values: | Discussion name | Mass number in periodic table | And I press "Split" Then I should see "Mass number in periodic table" And I follow "Study discussions" And I should see "Teacher 1" in the "Photosynthesis" "table_row" # Confirm that the last post author has been updated. And I should not see "Student 2" in the "Photosynthesis" "table_row" # Confirm that the current author has been shown for the new split discussion. And I should see "Student 1" in the "Mass number in periodic table" "table_row"
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